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Nataly [62]
2 years ago
15

6) A standard deck has 52 cards, and contains 13 cards of each of the four suits: diamonds, spades, hearts, and clubs. What is t

he
probability that you choose a diamond, given that you have already chosen a diamond and have not replaced it?
Mathematics
1 answer:
Crazy boy [7]2 years ago
6 0

Answer:

\dfrac{12}{51}\cong\dfrac{4}{17}

Step-by-step explanation:

You have 52 cards in a deck and 13 cards of each suit.

The probability of picking a diamond in a complete deck of cards is:

\dfrac {13}{52}

Or the probability is 13 put of 52.

Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

\dfrac{12}{51}

If we simplify it you will have a probability of:

\dfrac{4}{17}

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Calculate the value for each determinant:
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Answer:

Step-by-step explanation:

\begin{vmatrix}3 & -1\\ -3 & 4\end{vmatrix}=(3\times 4)-(-1)\times (-3)

               = 12 - 3

               = 9

\begin{vmatrix}8 & -1\\ -4 & -1\end{vmatrix}=8\times(-1)-(-1)\times(-4)

               = -8 - 4

               = -12

\begin{vmatrix}-12 & -1\\ 12 & 5\end{vmatrix}=(-12)\times(5)-(-1)\times(12)

                = -60 + 12

                = -48

\begin{vmatrix}2 & -1\\ 2 & -1\end{vmatrix}=2\times(-1)-(2)\times(-1)

            = -2 + 2

            = 0

\begin{vmatrix}0 & -1\\ 17 & 4\end{vmatrix}=0\times(4)-(-1)\times(17)

              = 17

\begin{vmatrix}1 & 0\\ 0 & 1\end{vmatrix}=1\times(1)-(0)\times(0)

          = 1

6 0
2 years ago
Read 2 more answers
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