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Nataly [62]
3 years ago
15

6) A standard deck has 52 cards, and contains 13 cards of each of the four suits: diamonds, spades, hearts, and clubs. What is t

he
probability that you choose a diamond, given that you have already chosen a diamond and have not replaced it?
Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

\dfrac{12}{51}\cong\dfrac{4}{17}

Step-by-step explanation:

You have 52 cards in a deck and 13 cards of each suit.

The probability of picking a diamond in a complete deck of cards is:

\dfrac {13}{52}

Or the probability is 13 put of 52.

Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

\dfrac{12}{51}

If we simplify it you will have a probability of:

\dfrac{4}{17}

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Answer:

A stem and leaf plot is a special table where each data value is split into a "stem" (the first digit or digits) and a "leaf" (usually the last digit). The "stem" values are listed down, and the "leaf" values go right (or left) from the stem values.

Step-by-step explanation:

Example: Long Jump

Sam got his friends to do a long jump and got these results:

long jump

2.3, 2.5, 2.5, 2.7, 2.8 3.2, 3.6, 3.6, 4.5, 5.0

And here is the stem-and-leaf plot:

Stem Leaf

2 3 5 5 7 8

3 2 6 6

4 5

5 0

Stem "2" Leaf "3" means 2.3

Note:

Say what the stem and leaf mean (Stem "2" Leaf "3" means 2.3)

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It is OK to repeat a leaf value

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4 years ago
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Answer:

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Step-by-step explanation:

its simple math

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Step-by-step explanation:

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Kia paid $10 for two charms. The price of each charm was a multiple of $2. What are the possible prices for the charms?
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\large{|\underline{\mathtt{\red{a}\blue{x}\orange{i}\pink{s}\blue{ \: }\purple{of}\green{ \: }\red{sy}\blue{mm}\orange{etry}}}}

\large \sf \: x =  \frac{7}{2}

\large{|\underline{\mathtt{\red{m}\blue{a}\orange{x}\pink{i}\blue{m}\purple{u}\green{m}\red{ \: }\blue{v}  \red{a}  \pink{l} \purple{u}\orange{e}}}}

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