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Yakvenalex [24]
3 years ago
11

2 After a hailstorm, a large car dealership wants to determine the proportion of cars that have damage. The service department r

andomly selects 50 cars on the dealership lot, examines them, and finds that 11 cars have damage. They want to construct a 99% confidence interval for the true proportion of cars with damage from the storm. Are the conditions for inference met? O Yes, the conditions for inference are met No, the 10% condition is not met No, the randomness condition is not met No, the Large Counts Condition is not met. ​
Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

Yes, the conditions for inference are met

Step-by-step explanation:

Conditions for inference:

To build a confidence interval for a population proportion, the sample must have at least 10 successes and 10 failures.

In this question:

50 cars, 11 have damage and 50 - 11 = 39 do not.

Since both the number of sucesses and of failures is above 10, conditions for inference are met.

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2 1/4 miles per hour.
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Conducting financial transactions through the internet on your cell phone is known as
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I think the answer is D
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2 qt/min= how many gal/s​
S_A_V [24]

The flow rate is 2 quarts per minute. There are 4 quarts in a US gallon, so 2 quarts divide 4 quarts per US gallon = 0.5 gallons per minute There are 60 seconds in a minute, so the flow rate is 0.5 gallons per minute divide 60 seconds per minute = 0.0083 gallons per second

 

 

4 0
4 years ago
Alex is thinking of a number. He multiplies it by 1,000 then divided it by 10.
sergeinik [125]
Solutions 

1) <span>Lets use n as alex's number 
</span>⇒ n x 1000
⇒ n ÷ 10 
⇒ = 475 


To solve the problem do the opposite steps 

475 ÷ 1000 =  n
n = <span>0.475
</span>
0.475 x 10 = n 
n = 4.75

CHECK YOUR WORK 

4.75 x 1000 = 4750
4750 ÷ 10 = 475 

The answer is correct 

⇒ The answer Alex is thinking of is 4.75





6 0
3 years ago
Read 2 more answers
In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu
Leya [2.2K]

Explanation:

The equation of comet E is given below as

\frac{(y+16)^2}{400}+\frac{x^2}{144}=1

The equation of comet H is modelled below as

\frac{(y+13)^2}{144}-\frac{x^2}{25}=1

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}

Whise center is

\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}

By comparing coefficient, we will have

\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}

Hence,

The vertex of comet E will be

\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}

The vertex of comet E is

(12,0),(-12,0)

Part C:

It is the foci forboth comets

\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\  \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}

Hence,

The foci will be

\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}

5 0
1 year ago
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