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3 years ago

Please help!! Only answer if you know the answer. Thank you.

Mathematics

2 answers:

drek231 [11]3 years ago

7 0

Answer:

Step-by-step explanation:

OT Weekly Pay

Tim Carter: 10 40x5.15= 206 5.15 x 1.5=7.725

7.725 x 10 = 77.25 206 + 77.25 = $283.25

Jesse Jones: 7.5 40x5.15= 206 5.15 x 1.5 = 7.725

7.725 x 7.5 = 57.9375 = 57.94

206 + 57.94 = $263.94

Barbara Burns: 4 40x5.15= 206 5.15x1.5 = 7.725

7.725 x 4 = 30.90 206 + 30.90 = $236.90

Vedmedyk [2.9K]3 years ago

3 0

ANSWER: Tim Carter's weekly pay was $282.25.

I will work on Tim Carter's weekly pay. Because he worked 50 hours, and there are 40 regular hours, he worked 10 overtime hours.

To find out his regular pay, we need to multiply his regular pay by his regular hours.

$40 * 5.15 = 206$

Tim Carter makes $206 for his regular hours. To find out his overtime pay, we need to multiply his regular pay by his overtime hours, then multiply that product by 1.5.

$10 * 5.15 = 51.5\\\\51.5 * 1.5 = 77.25$

Tim Carter makes $77.25 for his overtime hours. Lastly, add the regular pay and his overtime pay to get his weekly pay.

$206 + 77.25 = 283.25$

Tim Carter's weekly pay was $283.25.

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Answer:

a. attached graph; zero real: 2

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Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

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2 | 1 4 6 -36

1 6 18 0

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1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

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Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

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By using partial fraction decomposition:

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Now; we have to relate like terms on both sides; we have:

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$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

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$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

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$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

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