The ratio of female learners to male learners in a class is 3:2. If there are 30 female learners in the class, work out:

Mathematics

1 answer:

saul85 [17]2 years ago

3 0

Answer:

20 male learners
Total number of learners is 50

Step-by-step explanation:

(See attachment below)

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What’s the answer for this one??

KIM [24]

Answer:

It is the second one.

Step-by-step explanation:

a and e are equal because they are mirrored. d and b are equal because they are on the same line and at the same point where the parallel lines go through. b and f are also mirrored. That leaves c and e which don't match.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=71%20-%205x%20%3D%209x%20-%2013" id="TexFormula1" title="71 - 5x = 9x - 13" alt="71 - 5x = 9x

Sav [38]

You need to isolate x.

71 - 5x = 9x - 13

Add 13 to both sides.

84 - 5x = 9x

Add 5x to both sides.

84 = 14x

Divide both sides by 14.

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<h3>The answer is x = 6.</h3>

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3 years ago

Find p(2) for p(x)=x^4-2x^3-6x^2+5

Ede4ka [16]

(2)^4-2(2)^3-6(2)^2+5
16-64-144+5
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4 0

3 years ago

Motorola used the normal distribution to determine the probability of defects and the number

vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

$\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z$