Answer:
(u+2)-8
Step-by-step explanation:
sum is addition, less than is subtraction
Answer:
To stay within budget, she must use 4.4 gigabytes.
Step-by-step explanation:
Giving the following information:
Fixed cost= $57.50 per month
Variable cost= $4 per gigabyte.
She wants to keep her bill at $75.10 per month.
<u>First, we need to establish the total cost formula:</u>
Total cost= 57.5 + 4*x
x= number of gigabytes
<u>Now, we isolate x:</u>
75.1= 57.5 + 4x
17.6/4= x
4.4= x
To stay within budget, she must use 4.4 gigabytes.
Answer:
260.1615 ; 70.688 ; (53.787 ; 103.304)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Data:
242.87
260.93
194.19
260.76
355.36
346.32
165.37
250.08
326.76
283.56
212
284.08
139.16
436.72
240.87
310.41
223.73
181.25
238.2
250.61
Using calculator :
Sample mean = ΣX / n
Sample mean = 5203.23 / 20
Sample mean, m = 260.1615
Sample mean, m = 260.2
Sample standard deviation (s) :
Σ(X - m) / n - 1
= 70.688
= 70.7
((n-1)*s²) / ²0. 975, 19 ; ((n-1)*s²) / ²0.025, 19
95% confidence interval :
(53.787 ; 103.304)
Answer:
The common difference is -4/3.
Step-by-step explanation:
Recall that the direct formula for an arithmetic sequence is given by:
Where <em>n</em> is the <em>n</em>th term, <em>a</em> is the initial term, and <em>d</em> is the common difference.
We are given that the first term <em>a</em> is 31.
We also know that the 28th term is -5. Hence, <em>x</em>₂₈ = -5. Substitute:
Solve for <em>d</em>. Simplify:
Thus:
Divide both sides by 27. Hence, the common difference is:
Answer:
A(r) = √2 * r
A(r) Domain is R { r ; r > 0}
Step-by-step explanation:
Diagonals of a square intercept each other in a 90° angle. The four triangles resulting from diagonal interception are equal and are isosceles triangles, with hipotenuse a side of the square
Therefore we apply Pythagoras theorem
Let x be side of square, and r radius of the circle, ( diagonals touch the circle) then
x² = r² + r²
x² = 2r²
x = √2 * r
Now Aea of square is :
A = L² where L is square side
A(r) = √2 * r
Domain of A(r) = R { r, r > 0}
