We have to round the value of 0.1561 to the nearest tenth.
The number after decimal is the number at tenth place. Consider the number to the right of the tenths place and use the number to determine if you will round up or stay the same. Notice that the number to the right of tenth place is more than or equal to 5 or less than 5. If that number is greater than or equal to 5, then the number will round up but if that number is less than 5, then the number will not round up. It will remain same.
Let us consider the given number 0.1561
The number at tenths place is 1
The number after the tenths place is 5 (which is either greater than or equal to 5)
So, the number will round up to 0.2
Answer: A. 138 times
How?
During that time period there were 23 days so 23 multiplied by the amount of times played per day (6)
You get the answer 138
Since the sixth term is 1215 and the 5th term is 405, we know each term is 3 times more than the last.
Let 'n' represent the first term, then the sum of the first 9 terms can be written as:
n+3n+9n+27n+81n+243n+729n+2187n+6561n
which sinplifies to 9841n
since each term is 3 times the last, the first term must be 405 divided by 3, 4 times in total, which is 5
Now subsitute 'n' for 5, and we get 9841(5)
which is 49205 which is the answer.
Hope this helps
Yes. Your answer is correct
Answer:
Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.
Least common multiple (LCM) of 19600 and 19619 is 384532400.
