The answer is C i took the test a couple days ago
Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
(Given)
(Common angle)
(Given)
In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
(SAS congruence postulate)
Hence proved.
Remember that the decimal point is pronounced as "and".
To the right of the decimals, we have 100 thousandths.
<em><u>Three and one hundred thousandths</u></em>
Experimental probability is doing a test and basing probability on that.
Like if you roll a dice 100 times and 6 comes up 21 times, the
experimental probability is 21%.
Answer:
1. Perimeter = 8x m
2. Area = 3x² m²
Step-by-step explanation:
From the question given above, the following data were obtained:
Breadth (B) = x m
Length (L) = 3B = 3x m
Perimeter (P) =?
Area(A) =?
1. Determination of the perimeter of the rectangle.
Breadth (B) = x m
Length (L) = 3x m
Perimeter (P) =?
P = 2(L + B)
P = 2(3x + x)
P = 2(4x)
P = 8x m
Thus, the perimeter of the rectangle is 8x m
2. Determination of the area of the rectangle.
Breadth (B) = x m
Length (L) = 3x m
Area(A) =?
A = L × B
A = 3x × x
A = 3x² m²
Thus, the area of the rectangle is 3x² m²