The ratio of dogs to cats in the neighborhood was 2 to 3. If there were 30 dogs in the neighborhood, how many cats were there?

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

Answer: 45 cats

Step-by-step explanation: since you got 30 dogs. 2x15= 30 so to get the number of cats do 3x 15= 45cats

You might be interested in

What is the answer to this question

DanielleElmas [232]

Answer:

Step-by-step explanation:

the angle on top is the same because the lengths of the lines that meet to "H" are the same.

7 0

3 years ago

Factor -y - 8.<br> Please hurry it’s timed

max2010maxim [7]

Answer:

need more info

Step-by-step explanation:

3 0

3 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$