M = (y2-y1)/(x2-x1)
= (4-14)/3-1
= -10/2
= -5
Answer:
46.07
Step-by-step explanation:
CAH (cosine=adjacent/hypotenuse)
cos (71)=15 (adjacent)/x (hypotenuse)
x=15/cos(71)
x=46.07
Answer:
Mass of the cat = 16800kg
Step-by-step explanation:
The volume of the box = its length * its breath * its height- 4m × 3m × 2m = 24
The standard density of water is 1000 Kg/
By Archimedes principle, the mass of a body floating body is equivalent to the mass of the volume liquid displaced
in this case we have
Mass of water displaced = Density of the water × Volume of the water displaced = 1000 Kg/
× 24
= 24000kg
The mass of the box = Box density × Box volume = 24
× 300kg/
= 7200 kg Hence the mass of water displaced = mass of the foating box + mass of th cat
24000kg = mass of cat +7200kg
mass of cat = 24000kg - 7200kg = 16800kg
Answer:
-2/3x
Step-by-step explanation:
1.) use the slope equation (y2-y1)/(x2-x1)
2.) substitute the points into the equation (2-4)/(2--1)
3.) solve the equation (2-4= -2) / (2--1=3)
4.) the slope is -2/3