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Semmy [17]
2 years ago
10

Which graph best represents a quadratic function that has only one zero?

Mathematics
2 answers:
GenaCL600 [577]2 years ago
8 0

Answer:

B

Step-by-step explanation:

A has 2 it crosses the x axis 2x

B Has 1.

C has 2

D has none since it never touched the x axis

Liono4ka [1.6K]2 years ago
7 0

Answer:

B

Step-by-step explanation:

got a 100 on my test

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B). 10.63
Because 7^2=49 and 8^2=64 then 49+64=113 then the square root of 113 is 10.63
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How many 1x1 unit cubes would equal the volume of the figure shown?
motikmotik
D 3500 kk bye now ! :))
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3 years ago
What is the value of StartFraction 1.6 times 10 Superscript 14 Baseline Over 3.2 times 10 Superscript 7 Baseline EndFraction in
Helga [31]

Answer:

5.0 times 10 Superscript 6

Step-by-step explanation:

What is the value of StartFraction 1.6 times 10 Superscript 14 Baseline Over 3.2 times 10 Superscript 7 Baseline?

This is represented mathematically as:

1.6 × 10¹⁴/ 3.2 × 10⁷

Solving for this

1.6 × 10¹⁴/ 3.2 × 10⁷

= [1.6/3.2] × 10¹⁴-⁷

= 5 × 10⁶

= 5.0 times 10 Superscript 6

4 0
3 years ago
the angle theta is located in quadrant 1 and cos of theta is 3/8. what is the value of sin of theta ?
ra1l [238]

Answer: sin of theta = (√55)/8

Step-by-step explanation:

Cosine is the x-value divided by the hypotenuse. We now know that since cosine is 3/8, that the hypotenuse is 8. In order to find the third side of the triangle (which would be the v-value), we must use Pythagorean theorem. The third side is square root 55. Sine equals the y-value divides by the hypotenuse. We know both of those values, so Sine of theta = square root of 55 divided by 8.

8 0
3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
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