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2 years ago

Hi,please someone can help me i'm lost..

Mathematics

1 answer:

andreyandreev [35.5K]2 years ago

3 0

Answer:

let the number be n

$\frac{n}{6} +6=2\\\\\frac{n}{6} = -4\\\\n = -24$

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Please answer these and I will give brainliest!!!

ollegr [7]

Answer:

#1. 1232 feet per minute

#2. $14.81 per second

#3. 46.93 feet per second

Hope This Helps!

And that it's right!

4 0

3 years ago

John took a 5 ½ mile walk to his friend’s house. He left at 11 a.m. and arrived at his friend’s house at 1 p.m. What was John’s

olganol [36]

Answer:

5.5 miles over 2 hours--> 5.5/2= 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours --> 5.5/2.5= 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2= 0.55) 0.55 miles per hour lower on the return trip

Step-by-step explanation:

I hope this helps you :)

-KeairaDickson

7 0

2 years ago

What is m∠D? Enter your answer in the box.

Alex73 [517]

Answer:

D = 32

Step-by-step explanation:

A+ B + E = 180 since they form a triangle

14+ 45 + E = 180

E = 180 -14-45

E =121

E on either triangle is the same since they are vertical angles

C+D+E = 180 since they form a triangle

27+ D + 121 = 180

D = 180-121-27

D =32

3 0

3 years ago

Translate to words : 5(x+3)-6+7x

UkoKoshka [18]

5x+15-6+7x
15-6= 9.
5=7= 12
12x+9 .

6 0

2 years ago

Read 2 more answers

Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.

nataly862011 [7]

Answer: 110 feet per second

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

$S1=\frac{45*5280}{3600}=66$

$S2=\frac{60*5280}{3600}=88$

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

$h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}$

$h=\sqrt{12100}=110$

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

7 0

2 years ago