What is the constant of proportionality

Mathematics

1 answer:

babymother [125]3 years ago

5 0

Answer:

1/2

Step-by-step explanation:

1/2 x 1/2 = 1/4

3/4 x 1/2 = 3/8

1/1 x 1/2 = 1/2

5/4 x 1/2 = 5/8

(5/4 = 1 1/4)

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In the town zoo 3/8 of the animals are birds. Of the birds 4/15 are birds of prey. What fraction of the animals are nirds of pre

poizon [28]

3/8 of the animals are birds
of the birds: 4/15 are birds of prey

If you want to know what fraction of the animals at the zoo are birds of prey, you can calculate this using the following steps:

4/15 * 3/8 = 12 / (15*8) = 1 / (5*2) = 1 / 10 = 0.1

Result: In the town zoo, 1/10 of animals are birds of prey.

5 0

3 years ago

How to solve 2x-1/2=3-x

ValentinkaMS [17]

To solve for x:
Move all the terms containing "x" to the left side of the equation. Do this by adding x to both sides.

2x+x=3x. The new equation is:
3x-1/2=3

Now, move all terms not containing "x" to the right side of the equation. Do this by adding 1/2 to both sides.
3x=3+1/2 The new equation is:
3x=3 1/2, or 3.5

The final step is to isolate x. To do so, divide each side by 3.
3x/3 = 3 1/2 /3 The new equation is:
x=1 1/6

5 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$