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Setler [38]
3 years ago
13

Please help!!!!! i will give brainliest!

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

Option 1 and 4

Step-by-step explanation:

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SOMEONE HELP CUASE I ONLY HAVE 30 MINUTES BEFORE I TURN THIS IN! ASAP!!!!!!!The first hexagon is dilated to form the second hexa
marishachu [46]

Answer:

the scale factor is 2

this represents enlargement

Step-by-step explanation:

3 0
3 years ago
What are the solutions to the equation x2 + 6 = 87? A. –10 and 10 B. The equation has no solutions. C. –6 and 6 D. –9 and 9
kakasveta [241]
X² + 6 = 87
<u>     - 6   - 6</u>
       x² = 81
       x = <u>+</u>9
x = 9    U    x = -9
The solution set is equal to D. {<u>+</u>9}.
8 0
4 years ago
There are some hats in a box. 1/6 of them are red, 1/3 of blue, and 3/7 of the remainder are green. If there are 27 green hats,
yarga [219]
1/6 are red and 1/3 are blue 
<span>that means 1/6 + 2/6 = 3/6 = 1/2 are either red are blue </span>
<span>3/7 of the remainder is 3/14 of the total </span>
<span>3/14 x = 27 </span>
<span>x = 27(14/3) = 126 </span>

<span>there are 126 caps </span>
<span>126 / 6 = 21 are red </span>
<span>126 / 3 = 42 are blue </span>
<span>there are 63 left, of which 3/7 are green </span>
<span>3/7 (63) = 27 ==> 27 green caps </span>

<span>total of 126 caps

Hope this helps :)</span>
4 0
3 years ago
Read 2 more answers
a used automobile dealership recently reduced the price of a used compact car by 10 % if the price of the car before discount wa
Delvig [45]

Answer: The new price is $3350.


8 0
4 years ago
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On a camping trip you bring 12 items for 4 dinners. For each dinner you use 3 items. In how many ways can you choose items for t
Rashid [163]

Answer:

  • 220 options, 84 options, 20 options, 1 option

Step-by-step explanation:

<h3>The first dinner</h3>

Combinations of 3 out of 12 items

  • 12C3 = 12!/(12-3)!3! = 12!/9!3! = 12*11*10/2*3 = 220
<h3>The second dinner</h3>

Combinations 3 out of remaining 9 items

  • 9C3 = 9!/(9 - 3)!3! = 9!/6!3! = 9*8*7/2*3 = 84
<h3>The third dinner</h3>

Combinations of 3 out of remaining 6 items

  • 6C3 = 6!/(6 - 3)!3! = 6!/3!3! = 6*5*4/2*3 = 20
<h3>The fourth dinner</h3>

Combinations of 3 out of 3 remaining items

  • 3C3 = 3!/(3 - 3)!3! = 3!/0!3! = 1
6 0
3 years ago
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