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Kitty [74]
3 years ago
7

Suppose you note that there are congruent vertical angles in the triangles. Can you now use the ASA Postulate, the AAS Theorem,

or both to prove the triangles congruent?
Mathematics
1 answer:
ad-work [718]3 years ago
6 0
You can use both to prove the triangle is congruent.

So either ASA or AAS Theorem.

Hope this helped! :D
You might be interested in
If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4? a. 3.75 b. 1.67 c. 0.1 d. 7.5 Please select the best
REY [17]
Because y varies inversely as x, therefore
y= \frac{k}{x}
where k =  constant.

When x = 6, y = 2.5. Ther efore
\frac{k}{6} = 2.5
Cross multiply.
k = 6 x 2.5 = 15

The equation is
y =  \frac{15}{x}

When x = 4, obtain
y =  \frac{15}{4}= 3.75

Answer: a. 3.75

8 0
3 years ago
Read 2 more answers
Pizzeria Napoli sells a round pizza with diameter 16 inches and a square pizza with side length 15 inches. Which of the two shap
zavuch27 [327]

Answer: Square, 24 square inches

Step-by-step explanation:

Given

Diameter of round pizza d=16\ in.

Side of square pizza a=15\ in.

Area of circle \pi r^2

The area of a square is a^2

\therefore \text{Area of round Pizza}=\pi \times (\frac{16}{2})^2\\\Rightarrow A_1=\pi \times 8^2=201.088\ in.^2

The area of square pizza is

A_2=15^2=225\ in.^2

Clearly, the area of square pizza is more and the difference in their area is

\Rightarrow A_2-A_1=225-201.088=23.91\approx\ 24\ in.^2

6 0
2 years ago
Hello<br><img src="https://tex.z-dn.net/?f=.52.22.2." id="TexFormula1" title=".52.22.2." alt=".52.22.2." align="absmiddle" class
Rom4ik [11]

Uhh..not in a mood for a meet, k? Maybe later hun~~

8 0
3 years ago
What is the y-intercept of the line shown?
Marta_Voda [28]

Answer:

y-intercept = 3

Step-by-step explanation:

value that's on the y - axis

4 0
3 years ago
When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w
deff fn [24]

Answer:

A 90% confidence interval for <em>p</em> will be <u>narrower </u>than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - <em>α</em>) % confidence interval for a population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Here \hat p is the sample proportion.

The margin of error of the confidence interval is:

MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The MOE is dependent on:

  1. Confidence level
  2. Standard deviation
  3. Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645

And the critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for <em>p</em> will be narrower than the 99% confidence interval.

6 0
3 years ago
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