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insens350 [35]
3 years ago
13

Please help!!!!!

Mathematics
2 answers:
netineya [11]3 years ago
8 0
The answer is: t<span>he triangles are not similar.</span>
olchik [2.2K]3 years ago
8 0

Answer: the triangles are not simlar

Step-by-step explanation: took the test

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What is the measure of angle 3?
Marrrta [24]

Answer:

can you insert a picture or other information to answer this pls

Step-by-step explanation:

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A delivery service charges $1.25 for
choli [55]

Answer: 6\ \text{miles}

Step-by-step explanation:

Given

A delivery service charge \$1.25 for each delivery

and an additional \$0.75 for each mile traveled

Suppose, x miles are covered

The charge is given by

\Rightarrow 5.75=1.25+0.75x\\\Rightarrow 4.5=0.75x\\\Rightarrow x=6\ \text{miles}

Therefore, driver traveled 6 miles for delivery

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A stock market fell 40 points each day for
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5 0
3 years ago
Read 2 more answers
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
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