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Shkiper50 [21]
3 years ago
5

Benito runs 1/10 of a mile each day. which shows how to find the number of days it will take for benito to run 3/5 of a mile

Mathematics
1 answer:
damaskus [11]3 years ago
8 0

I would say  divide 3/5 by 1/10

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The Software Company earned 2,247,852,199 dollars last year. This year they earned 3,000,962,245 dollars. Which is the best esti
RSB [31]

You know the following information:

1. The amount of money (in dollars) earned last year was:

2,247,852,199

2. The amount of money (in dollars) earned this year, is:

3,000,962,245

Then, to estimate the sum (the total amount of money the Software Company earned in those two years, you can round the numbers to the nearest billion.

Having:

2,247,852,199

You need to look at the digit located in the Hundred millions place. Notice that this is:

2

Then, since:

2

You need can't round up. Then:

2,247,852,199\approx2,000,000,000

Now, having:

3,000,962,245

You can identify that the digit in the Hundred millions place is

0

Therefore:

3,000,962,245\approx3,000,000,000

Now you can add the numbers rounded:

2,000,000,000+3,000,000,000=5,000,000,000

Hence, the answer is: Option B.

5 0
1 year ago
Answer for 23 plz plz plz
den301095 [7]

Answer:

A₍ₙ₎ = - 74 + (n-1) x 6

Step-by-step explanation:

A₍ₙ₎ = A₍₁₎ + (n-1) x d

A₍₁₈₎ = 28 = A₍₁₎ + 17 x d  ..... (1)

A₍₄₀₎ = 160 = A₍₁₎ + 39 x d  .....(2)

(2)-(1)    132 = 22d

d = 6

A₍₁₎ = 28 - 17 x 6 = -74

formula: A₍ₙ₎ = - 74 + (n-1) x 6

3 0
3 years ago
(25 1/8- 20.5) solve it
Sergeeva-Olga [200]

Answer:

the answer is 4.625 or 4 6/10

Step-by-step explanation:

I just used a calculator. hope this helps <3

5 0
2 years ago
Calc help pretty please
Gre4nikov [31]

Answer:

A.  77.4

Step-by-step explanation:

<u>Linear approximation formula</u>

L(x)=f(a)+f'(a)(x-a)

Given function:

f(x)=(x+1)^2

\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If  $y=f(u)$  and  $u=g(x)$  then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{\text{d}y}{\text{d}u}\times \dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}

\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If  $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}

\boxed{\begin{minipage}{4 cm}\underline{Differentiating $ax$}\\\\If  $y=ax$, then $\dfrac{\text{d}y}{\text{d}x}=a$\\\end{minipage}}

Use the chain rule to differentiate the function.

\textsf{Let }\:y=u^2\:\textsf{ where }u=(x+1)

Differentiate the two parts separately:

  y=u^2 \implies \dfrac{\text{d}y}{\text{d}u}=2u

  u=x+1 \implies \dfrac{\text{d}u}{\text{d}x}=1

Put everything back into the chain rule formula:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =2u \times 1\\ & = 2u \\ & = 2(x+1)\\ & = 2x+2 \end{aligned}

\textsf{Therefore, }\:f'(x)=2x+2..

The <u>linear approximation</u> at a = 8 is:

\begin{aligned}L(x) & =f(a)+f'(a)(x-a)\\\\\implies L(x) & = f(8)+f'(8)(x-8)\\& = (8+1)^2+(2(8)+2)(x-8)\\& = 81+18(x-8)\\& = 18x-63\end{aligned}

Finally, substitute x = 7.8 into the <u>linear approximation equation</u>:

\begin{aligned}\implies L(7.8) & =18(7.8)-63\\& = 140.4-63\\& = 77.4\end{aligned}

4 0
1 year ago
Read 2 more answers
the half life of polonium is 139 days. you have a brand new sample of polonium that will not be useful to you after 80% of the m
melamori03 [73]

The half-life of Po is 139 days, so its decay rate is

0.5 = e^(139k)  ==>  k = ln(0.5)/139

After some time t, 80% of the material will have decayed and you'll be left with a sample 20% of its original mass:

0.2 = e^(kt)  ==>  t = ln(0.2)/k = ln(0.2)/ln(0.5) * 139 = 322.748

so your sample is usable for about 323 days.

7 0
3 years ago
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