Answer ASAP!! Please! Will give brainliest!

Virgil has 1/6 of a birthday cake left over. He wants to share the leftover cake with 3 friends. What fraction of the original c

klemol [59]

Answer:

Each of the 4 people will get 1/24 of the original cake

Step-by-step explanation:

The fractional part of cake left out is 1/6

This remaining cake is to be divided among four people.

Thus, each person will get

fractional part of cake left/total number of people

i.e 1/6/4

= 1/24

Each of the 4 people will get 1/24 of the original cake

3 0

2 years ago

Write down the general equation of the normal distribution

Talja [164]

The following is the plot of the normal percent point function. where \phi is the cumulative distribution function of the standard normal distribution and Φ is the probability density function of the standard normal distribution.

8 0

2 years ago

4 loads of stone weigh 2/3 ton. Find the weight of 1 load of stone.

Zina [86]

<span>For computing this, follow this method: 4 loads of stone weigh 2/3 ton. 4loads---------------------2/3 1load---------------------? So it will be computed as 1x 2/3 /4 = 2/3x4= 1/3x2=1/6 the weight of 1 load of stone is 1/6 ton Hope this helps. Let me know if you need additional help!</span>

4 0

2 years ago

Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the

erma4kov [3.2K]

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

= $0.05 + $0.15

= $0.20

Compute the total demand as follows:

Total demand = Mean × n

= 2000 × 4

= 8000

Compute the standard deviation of total demand as follows:

$SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000$

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

= $2.15 - $0.20

= $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

$\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}$

$=\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907$

Use Excel's NORMSINV{0.907} function to find the Z-score.

<em>z</em> = 1.322

Compute the optimal production quantity for the card as follows:

$\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\$

$=8000+(1.322\times 1000)\\=8000+1322\\=9322$

Thus, the optimal production quantity is 9,322 cards.

8 0

2 years ago

Can someone please help me with this ; The result of subtracting 2 from its opposite is _____. choices are 0 , 1 , 4 , -4

valina [46]

$-2-2=-4$
....................

6 0

2 years ago