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icang [17]
2 years ago
14

The ratio of Warrior fans to Laker fans at a basketball game was 5 to 3. If

Mathematics
2 answers:
djyliett [7]2 years ago
7 0

Answer:

35

Step-by-step explanation:

Create a proportion where x is the number of Warrior fans

\frac{5}{3} = \frac{x}{21}

Cross multiply and solve for x

105 = 3x

35 = x

So, there were 35 Warrior fans

max2010maxim [7]2 years ago
7 0

Answer:

\bf\huge  warrior \: fans = 35

Step-by-step explanation:

<h2>Given that :</h2>

  • The ratio of Warrior fans to Laker fans at a basketball game was 5 to 3.
  • If there were 21 Laker fans.

<h2>to find :</h2>

  • how many Warrior fans are there.

<h2>let us assume :</h2>

  • warrior fans is X .

<h2>explanation :</h2>

finding the warrior fans

⟼ warrior : laker fans = 5 : 3 = x : 21

⟼ 5 : 3 = x : 21

⟼ \frac{5}{3}  \times  \frac{x}{21}

⟼ x = 5 × 7

⟼ x = 35.

⟼ warriors fans = 35.

∴ laker fans is 21 and warriors fan is 35.

∴ warriors : laker fans = 5 : 3 = 35:21.

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Answer:

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Step-by-step explanation:

1) Given

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Let us learn about a formula:

P(A\ or\ B) = P(A) +P(B) -P(A\ and\ B)\\OR\\P(A\cup B) = P(A) +P(B) -P(A\cap B)

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Using above formula:

P(A\ or\ B) = P(A) +P(B) -P(A\ and\ B)\\\Rightarrow P(A\ or\ B) = 0.3 + 0.5 -0.2 = \bold{0.6}

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1) Given

P(A) = 0.4 and P(B) = 0.2

Let us learn about a formula:

P(A\ and\ B) = P(B) \times P(A/B)  for dependent events

P(A\ and\ B) = P(A) \times P(B) for independent events.

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Using the above formula for independent events:

P(A\ and\ B) = 0.4 \times 0.2 = \bold{0.08}

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Using above formula:

P(A\ and\ B) = P(B) \times P(A/B) = 0.2 \times 0.7 = \bold{0.14}

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Given that 10% of the nails made using a certain manufacturing process have a length less than 2.48 inches, while 5% have a leng
zvonat [6]

Answer:

The mean, μ is 2.5063 and

The standard deviation, σ = 2.0499 × 10⁻²

Step-by-step explanation:

Here we have

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z \sigma ={x- \mu}{} and

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3 years ago
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