-3y > x +18<br> y 2-4x<br> m=<br> 3/1

Which equation can be used to find 75 percent of 200? HELPNOWW

Karolina [17]

Answer:.75x200

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Prove the following limit. lim x → 5 3x − 8 = 7 SOLUTION 1. Preliminary analysis of the problem (guessing a value for δ). Let ε

Temka [501]

$\displaystyle\lim_{x\to5}3x-8=7$

means to say that for any given $\varepsilon>0$ , we can find $\delta$ such that anytime $|x-5|$ (i.e. the whenever $x$ is "close enough" to 5), we can guarantee that $|(3x-8)-7|$ (i.e. the value of $3x-8$ is "close enough" to the limit value).

What we want to end up with is

$|(3x-8)-7|=|3x-15|=3|x-5|$

Dividing both sides by 3 gives

$|x-5|$

which suggests $\delta=\dfrac\varepsilon3$ is a sufficient threshold.

The proof itself is essentially the reverse of this analysis: Let $\varepsilon>0$ be given. Then if

$|x-5|$

and so the limit is 7. QED

8 0

3 years ago

Pat and his friend rent an apartment together. Their total cost to move in included first months rent, last months rent and a se

zimovet [89]

Answer:

a.$375

Step-by-step explanation:

In order to calculate this you just have to keep in mind the amount of months that they paid in advance in the payment, so they had 2 months of rent fully paid in advance, we will represent that with "x", so we have 2x as the number of months, and it doesn´t say that they are paying unequal amounts of money so we will assume that they are paying half each of everything, so the equation will look like this:

$Total payment: 2 months of rent+security deposit$

If total payment= $1050 each, that means that for the two of them it´d be $2100, now we know that they paid 2 months plus a security deposit of $600, we just have to clear the payment to discover how much does the rent a month cost:

$Total payment: 2 months of rent+security deposit\\Tp=2x+600\\Tp-600=2x\\x=\frac{Tp-600}{2} \\x=\frac{2100-600}{2} \\x=750$

So one month of rent costs $750, if you divide that by 2, you get that Pat´s share of rent a month is $375.

6 0

3 years ago

A father is 25 years old . Six years ago he was 5 times as old as his son. Find the present age of Father and son.

raketka [301]

Answer:

Define F as fathers age and S as sons age right now.

Then now they are

(1) 3S = F

and six years ago they were

(2) 5*(S-6) = F-6

calculate 5*(S-6)

5S - 30 = F-6

Subtract left and right side by -F

Add 30 to left and right side

5S - F = 24

Put (2) 3S = F into the equation above

5S - 3S = 24

2S = 24

S = 12

insert result in (2) 3S = F

3*12 = F

36 = F

Step-by-step explanation:

So the son is 12 years, and the father is 36 years.

5 0

3 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago

-3y > x +18 y 2-4x m= 3/1