The optimum shape of such a box is half a cube. The corresponding cube will have a volume of 2×256 ft³ = 512 ft³ = (8 ft)³. Such a box has a square base that is 8 ft on a side. If the height is half that of the cube, it will be 4 ft.
The dimensions of your box will be 8 ft square by 4 ft high.
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If the base dimension is x ft, the area (quantity of material) is
... a = x² + 4x(256/x²)
... a = x² + 1024x⁻¹
Then the derivative of area with respect to x is
... a' = 2x -1024x⁻²
Setting this derivative to zero and solving for x gives the value of x for minimum area.
... 0 = 2x -1024/x²
... 512 = x³
... x = 8 . . . . . . . . same as above.
It would help if we represent the information in form of two-ways table as shown below
The number of students who are not on probation is 104 students
There are 23 students who are not on probation and is satisfied is 81 students
The probability of students not on probation and is satisfied is 81/104
Answer:
All given information leads to conclusion described on statement. (
)
Step-by-step explanation:
The strategy of problem consist in make a mathematical demonstration from given information. There are two assumptions: i)
is a point of segment
and ii)
is the midpoint of
. We proceed to perform the demonstration:
1)
,
is the midpoint of
. Given.
2)
Definition of midpoint.
3)
Definition of segment/Result.
All given information leads to conclusion described on statement. (
)