Answer:
x = 16
Step-by-step explanation:
The two marked angles are supplementary:
(7x -2) +(4x +6) = 180
11x +4 = 180
11x = 176
x = 176/11 = 16
The value of x is 16.
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<em>Additional comment</em>
The angle on the left is 110°; the one on the right is 70°, so that answer checks.
These marked angles are called "consecutive exterior" angles. Just as "consecutive interior" angles are supplementary, so are consecutive exterior angles.
Essentially, all of the obtuse angles are congruent, as are all of the acute angles. The obtuse angles are supplementary to the acute angles.
Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
306/6 is 51 is you add one to one side and take away the other the six numbers become: 46, 48, 50, 52, 54, 56 as you added one to one side substituting the other you took away from, therefore the smallest would be 46.
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
y = mx + b
-3 = -2(-5) + b
-3 = 10 + b
-13 = b
y = -2m - 13
The line would pass through -13 on the y-axis and it would go down 2 and move to the right 1 for every new point.
Hope this helps! ;)
