To solve this, we can use the percent change formula shown in the picture attached below. $x_{2}$ is the new value, $x_{1}$ is the old value, and $C$ represents the change. For this problem, 80 is the new value and 64 is the old value. Let's plug those numbers into the formula and solve for the percent change:

$C = \frac{(80-64)}{64} \\$ × $100$

$C = \frac{16}{64}$ × $100$

$C = 0.25$ × $100$

$C = 25%$

Thus, the answer is 25%.

7 0

3 years ago

Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

dybincka [34]

Answer:

$\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}$

Step-by-step explanation:

$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

3 0

3 years ago