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mojhsa [17]
3 years ago
9

The half-life of a radioactive kind of thallium is 3 minutes. If you start with 80 grams of it,

Mathematics
1 answer:
padilas [110]3 years ago
4 0
- After 3 minutes you have half. 40grams
- After 3 more minutes you have half of that. 20 grams
- After the last 3 minutes you have half of that. 10 grams
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Determine if the given vectors are linearly independent. u = −4 0 −3 , v = −2 −1 4 , w = −8 2 −17
lesya [120]

These three vectors are linearly <u>dependent</u> (details are in the attachment).

6 0
4 years ago
Give me a trick on how to multiply a fraction by a while number
Vesnalui [34]

Answer:

look at the explanation

<em><u>explanation</u></em>

example

6 × 3/4

do 6 ×3

6×4

u will get 18/24 and then simplify

4 0
3 years ago
Find the product of 3 and the linear equation, and solve for both equations for y.
krok68 [10]

Answer:

Part 1) The product of 3 and 2y-4x=8 is 6y-12x=24

Part 2) The original equation in slope intercept form is y=2x+4

Part 3) The new equation in slope intercept form is y=2x+4

Step-by-step explanation:

we have

2y-4x=8

step 1

Find out the product of 3 and 2y-4x=8

Multiply both sides by 3

3(2y-4x)=3(8)

Apply distributive property both sides

6y-12x=24

step 2

Find out the original equation in slope intercept form

The equation of the line in slope intercept form is

y=mx+b

we have

2y-4x=8

Solve for y

That means ----> Isolate the variable y

Adds 4x both sides

2y=4x+8

Divide by 2 both sides

y=(4x+8)/2

Simplify

y=2x+4

step 3

Find out the new equation in slope intercept form

The equation of the line in slope intercept form is

y=mx+b

we have

6y-12x=24

Solve for y

That means ----> Isolate the variable y

Adds 12x both sides

6y=12x+24

Divide by 6 both sides

y=(12x+24)/6

Simplify

y=2x+4

8 0
4 years ago
Ble.<br> 6<br> co<br> 10<br> square units
Vlada [557]

Answer:

1/2×10×6=30

Step-by-step explanation:

H=6

L=10

therefore;

1/2×6×10=30

5 0
3 years ago
Read 2 more answers
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
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