Answer:
2•15k
Step-by-step explanation:
press ask for help i think it my help im also stumped on that
Answer:
Solving the equation
by completing the square method we get 
Option B is correct option.
Step-by-step explanation:
We need to solve the equation
by completing the square method.
For completing the square method: we need to follow: 
We are given:

Solving by completing the square

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.
So, adding and subtracting (3)^2

So, solving the equation
by completing the square method we get 
Option B is correct option.
Answer: Circumference = 7.85 inches
Concept:
Here, we need to know the idea of circumference.
The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.
Circumference = 2πr
r = radius
π = constant
Solve:
<u>Given information</u>
r = (1/2) d = (1/2) (2.5) = 1.25 inches
π = 3.14
<u>Given formula</u>
Circumference = 2πr
<u>Substitute values into the formula</u>
Circumference = 2 · (3.14) · (1.25)
<u>Simplify by multiplication</u>
Circumference = (2.5) · (2.14)
Circumference = 
Hope this helps!! :)
Please let me know if you have any questions
Answer:
The intersection of both lines.