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Ainat [17]
3 years ago
6

What is a fraction equation that equals 4

Mathematics
2 answers:
ella [17]3 years ago
8 0
16/4 could be reduced to 4
Nikitich [7]3 years ago
8 0

Any fraction that, when dividing the numerator and denominator, it'll give you 4.

For example:

8/2, which, when divided: 8/2 = 4

16/4, which, when divided: 16/4 = 4

hope this helps

<em>~Rise Above the Ordinary</em>

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Which expression gives the closest estimate of 228 – 179?
Oxana [17]

Answer:

show the picture

Step-by-step explanation:

7 0
2 years ago
Which point does not lie on the circle centered at (3, 2) with radius 5? A) (0, 6) B) (3, -3) C) (-2, 2) D) (3, 0)
vladimir1956 [14]

Answer:

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (3, 2) and r = 5, hence

(x - 3)² + (y - 2)² = 25 ← equation of circle

If an ordered pair lies on the circle then it satisfies the equation, if not then it does not lie on the circle.

Substitute the coordinates of the points into the left side of the equation of the circle and check validity.

A

(0 , 6) : (0 - 3)² + (6 - 2)² = 9 + 16 = 25 ← lies on circle

B

(3, - 3) : (3 - 3)² + (- 3 - 2)² = 0 + 25 = 25 ← lies on circle

C

(- 2, 2) : (- 2 - 3)² + (2 - 2)² = 25 + 0 = 25 ← lies on circle

D

(3, 0) : (3 - 3)² + (0 - 2)² = 0 + 4 = 4 ≠ 25 ← not on circle

7 0
3 years ago
Help me please help me help please
Anestetic [448]

Answer:

4

Step-by-step explanation:

-4/-1 = 4

6 0
2 years ago
The ellipse with x-intercepts (2, 0) and (-2, 0); y-intercepts (0, 4) and (0, -4).
masya89 [10]

Answer:

\dfrac{x^2}{4}+\dfrac{y^2}{16}=1

Step-by-step explanation:

If the ellipse has its x-intercepts at points (2, 0) and (-2, 0) and y-intercepts at points (0, 4) and (0, -4), then its symmetric across the y-axis and across the x-axis.

Moreover,

a=2\\ \\b=4

The equation of such ellipse is

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

Hence, the equation of the ellipse is

\dfrac{x^2}{2^2}+\dfrac{y^2}{4^2}=1\\ \\ \\\dfrac{x^2}{4}+\dfrac{y^2}{16}=1

3 0
3 years ago
Can someone answer this? thanks
nikitadnepr [17]
I think the answer is B
5 0
3 years ago
Read 2 more answers
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