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taurus [48]
3 years ago
8

Which of the following are statistical questions? Select all.

Mathematics
1 answer:
Lynna [10]3 years ago
6 0

c and e because statistical questions can be answered by collecting data that can have variability.

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The table below represents the height of a bird above the ground during flight, with p(t) representing height in feet and t repr
ddd [48]

Answer:

3.23

Step-by-step explanation:

6.26+6+3.41=15.67

15.67/7=3.23

I have mentioned time 7 sec from 3 to9

8 0
3 years ago
Read 2 more answers
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
What is the area of a square with a side length of 7 feet ? <br><br> HELP
Stells [14]

Answer:

49 square feet

Step-by-step explanation:

Area of square

=  {7}^{2}  \\  \\  = 49 \:  {ft}^{2}  \\

4 0
3 years ago
Graph the line.<br><br><br> y = −4x + 2
MrRissso [65]

Answer:

it rise over run so put 2y on graph count down 4 and move right 1

Step-by-step explanation:

8 0
3 years ago
I need help can anyone help me ​
labwork [276]
In 7 years, the car was 18,000 and after 5 years it is worth 10,500 so if you subtract 18000-10500=7500 and if you do 7500/5=1500 so this means that the car was going down 1500 in value every year.
5 0
2 years ago
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