2 years ago

Answer this question to get marked as brainliest!!!!!

1 answer:

4 0

(15^3)^3

the rest are equal to 15^6:)

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mario62 [17]

Answer:

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pickupchik [31]

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viva [34]

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mamaluj [8]

Answer:

3 7/8

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MrRissso [65]

The average value of $f(x)=4x^3-3x^2$ over [-1, 3] is

$\displaystyle\frac1{3-(-1)}\int_{-1}^3(4x^3-3x^2)\,\mathrm dx=\frac14\left(x^4-x^3\right)\bigg|_{-1}^3=\frac{(3^4-3^3)-(1+1)}4=\boxed{13}$

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3 years ago