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ycow [4]
3 years ago
8

How many real roots are there in x^2+bx-1=0​

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

In order to see how many real roots it has you have to see what the Δ is

So if Δ>0 then there are 2 real roots

If Δ=0 there is 1 real root

If Δ<0 no real root

And we know that:

Δ=b^2-4ac

So in the equation: Δ=b^2+4 and b^2 is always a number greater than or equal to 0 so when you add 4 to it, it is always greater than 0

So it has 2 real roots

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Terrell used wired fencing to form a border around a circular region vin his backyard. If the radius of the circular region was
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5 0
3 years ago
PLEASE QUICK NEED HELP FROM ANYONE!!!!Jorge earns a 9% commission on all of his sales. He had sales of $89,400 for the month. Ha
Bezzdna [24]
I have seen Your question many times before:

<span>Jorge earns a 9% commission on all of his sales. He had sales of $89,400 for the month. Harris works for a different company, and also sold $89,400 for the month but made $447 more than Jorge. What is Harris’ commission rate? please show your work.



Your work to the answer:
</span>Given that, Jorge's commission rate is 9% and his sales for the month  was $89,400, his commission was 9/100*$89,400=$8046.
Harris's sales for the month was also $89400 but he earned $477 more than Jorge, so his commission was $8046+$477=$8523
So his commission rate can be found by dividing his earnings by his sales and multiplying the quotient by 100.

Your final answer:
His commission rate was 8543/89400*100=9.53%(rounded to the nearest hundredth)


<em>Hope this helped!!!</em>



7 0
3 years ago
I have to repeat this question. But help me
fomenos
What do the terms of the expansion represent?


D: 3b-0.51b

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