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bonufazy [111]
3 years ago
15

The cost of 2 jackets and 3 skirts was sh 1800. After the cost of a jacket and that of a skirt was increased by 20%,the cost of

6 jackets and 2 skirts was sh4800,what is the new cost of a jacket and that of a skirt
Mathematics
1 answer:
nadya68 [22]3 years ago
3 0

Answer:

New cost of jacket = 1.2x=1.2\times 600=720\ \text{sh}

New costs of skirt = 1.2y=1.2\times 200=240\ \text{sh}

Step-by-step explanation:

Let original cost of jacket = x

original cost of skirt = y

The equation will be

2x+3y=1800

New cost of jacket = 1.2x

New costs of skirt = 1.2y

The equation will be

6(1.2x)+2(1.2y)=4800\\\Rightarrow 7.2x+2.4y=4800

The equations are

2x+3y=1800  \times 0.8

7.2x+2.4y=4800

1.6x+2.4y=1440

7.2x+2.4y=4800

Subtracting the above two equations we get

-5.6x=-3360\\\Rightarrow x=\dfrac{3360}{5.6}\\\Rightarrow x=600

7.2\times 600+2.4y=4800\\\Rightarrow y=\dfrac{4800-7.2\times 600}{2.4}\\\Rightarrow y=200

New cost of jacket = 1.2x=1.2\times 600=720\ \text{sh}

New costs of skirt = 1.2y=1.2\times 200=240\ \text{sh}.

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A travel agent is booking a trip to England, Scotland, Ireland, and France for a group of senior citizens. The agent sent survey
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Answer: 1

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Step-by-step explanation:

In the first vote, points are:

France = 15

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Ireland = 19

2nd vote

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Ireland = 16

3rd vote

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At the end of everything

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A child ate 30 grams of cereal for breakfast and her brother ate 40% more than that. How many grams of cereal did the brother ea
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An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

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(B) 0.25

(C) 0.40

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R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

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(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

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Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

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