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4 years ago

Please Answer this i will give brainliest

Mathematics

1 answer:

Tju [1.3M]4 years ago

6 0

B. 2 5/6 x 2 5/6 equals 8 1/36

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The length of a rectangle is 20 units more than its width. The area of the rectangle is x4−100.

Mice21 [21]

Answer:

$1. x^2-10$ because the area expression can be rewritten as $(x^2-10)(x^2+10)$ which equals $(x^2-10)((x^2-10)+20).$

Step-by-step explanation:

Area of the rectangle $=(x^4-100)$

$x^4-100=(x^2)^2-10^2\\$Applying difference of two squares: a^2-b^2=(a-b)(a+b)\\(x^2)^2-10^2=(x^2-10)(x^2+10)$

Since the length of a rectangle is 20 units more than its width.

$Width: x^2-10\\Length=x^2+10=x^2-10+20$

The correct option is therefore 1.

4 0

4 years ago

Read 2 more answers

At a particular restraunt, hamburgers are priced $3 each, 2 for $5 and 5 for $9. What is the maximum number of hamburgers that c

zepelin [54]

$9 + $9 + $9 + $9 + $9 + $3 = $48

5 + 5 + 5 + 5 + 5 + 1 = 26 hamburgers.

Hope that helps :)

5 0

3 years ago

|13x-4|+12 < 56 Anybody know this cuz I do

Ronch [10]

Answer:

$\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)$

Step-by-step explanation:

Inequalities with Absolute Value

We must recall the following rule:

$\text{If }|M|0$

Then:

$-N$

We have the following inequality:

$|13x-4|+12 < 56$

Subtracting 12:

$|13x-4|< 56-12$

$|13x-4|< 44$

Applying the rule:

$-44$

Adding 4:

$-44+4$

Operating:

$-40$

Dividing by 13:

$\displaystyle -\frac{40}{13}$

The solution expressed in interval form is:

$\boxed{\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)}$

8 0

3 years ago

Simplify these sums.☺ Could someone please help me answer these maths questions ☺

kkurt [141]

I)5n^11
ii) 6n^3
iii) 21n^13
v) 16n
vi) 8n
vii) 50n^5

3 0

4 years ago

433 round to the nearest 10

tankabanditka [31]

Answer:

433

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers