Answer:
1.32% of students have the chance to attend the charter school.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
This year the mean on the entrance exam was an 82 with a standard deviation of 4.5.
This means that 
a.What is the percentage of students who have the chance to attend the charter school?
Students who achieve a score of 92 or greater are admitted, which means that the proportion is 1 subtracted by the pvalue of Z when X = 92. So
has a pvalue of 0.9868
1 - 0.9868 = 0.0132
0.0132*100% = 1.32%
1.32% of students have the chance to attend the charter school.
Answer:
g(-2) = -1
Step-by-step explanation:
By looking at the graph, we can see that g(-2) where x = -2 is represented. Because x = -2, we can see that the y-value that correlates to this x-value is -1.
So g(-2) = -1.
Answer:
1. A(1;5), B(10;23), slope of 2
2. A(10;9), B(4;0), slope of 1.5
3. A(-35/4;6), B(9;-35/6), slope of -2/3
4. A(5;18), B(25,22), slope of 0.2
5. A(2/9;1/3), B(2/3,-1/3), slope of -1.5
Step-by-step explanation:
Substitute values with correct variable and slopemis coefficient of x when x and y-int. are on 1 side, y is on other side and has coefficient of 1. Hope it works!
Answer:
$84
Step-by-step explanation:
Simple Interest = Interest rate*Principle*number of years
= (3÷100)*$700*4
=$84
Write an equation system based on the problem
"Agatha is five times older than her son, Bob" could be written as:
a = 5b.......(first equation)
"Three years ago, she was nine times older" could be written as:
a - 3 = 9(b - 3)......(second equation)
Solve the equation system
To find the value of b, substitute 5b as a to the second equation
a - 3 = 9(b - 3)
5b - 3 = 9(b - 3)
5b - 3 = 9b - 27
5b - 9b = -27 + 3
-4b = -24
b = -24/-4
b = 6
Her son, Bob, is 6 years old
To find Agatha's age, substitute the value of b to the first equation
a = 5b
a = 5 × 6
a = 30
Agatha is 30 years old
