Translated
so the distance from A to A' should be the same as form B to B'
distance formula
distance between (x1,y1) and (x2,y2) is
![D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
so distance between (1,5) and (-2,1) is
![D=\sqrt{(-2-1)^2+(1-5)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28-2-1%29%5E2%2B%281-5%29%5E2%7D)
![D=\sqrt{(-3)^2+(-4)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28-3%29%5E2%2B%28-4%29%5E2%7D)
![D=\sqrt{9+16}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B9%2B16%7D)
![D=\sqrt{25}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B25%7D)
![D=5](https://tex.z-dn.net/?f=D%3D5)
the distance is 5 units
For example, if x/2=7, x would be equal to 7x2=14, bringing the whole number the variable is divided by to the other side of the equation.
Answer:
hence triangle can be formed with sides 5, 6,10
Step-by-step explanation:
it is fundamental principle of elementary geometry that sum of ant two sides of a triangle must be greater than the third side
here 5+6 is greater than 10
5+10 is greater than 6
6+10 is greater than 5
hence triangle can be formed with sides 5, 6,10
Answer:
I believe so, since it's still x/y
Answer:
y = -4x-4
Step-by-step explanation:
We need to find an equation of the line that passes through (1,0) and has a slope of m=-4.
The equation of a line is given by :
y = mx+c
Where
m is slope of line
Put all the values,
y = -4x+c
Put x = 1 and y = 0
So,
0 = -4(1)+c
c = -4
So, the required equation is :
y = -4x-4