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ale4655 [162]
3 years ago
9

If you can help me youre a legend :)

Mathematics
2 answers:
AleksandrR [38]3 years ago
4 0

Answer:

A. 9

B. 7

Step-by-step explanation:

A. 11 - 2 = 9

B. 1 + 6 = 7

Ierofanga [76]3 years ago
4 0
A)11-2=9
B)6+1=7
I think this is the answ
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99165+67894321-9872345​
julsineya [31]

Answer:

58121141

Step-by-step explanation:

99165+67894321= 67993486  

67993486-9872345= 58121141

6 0
3 years ago
at a point P on the parabola x^2=4ay a normal PK is drawn. From vertex O, a perpendicular OM is drawn to meet the normal at M. S
saveliy_v [14]
<span>Answer: Its too long to write here, so I will just state what I did. I let P=(2ap,ap^2) and Q=(2aq,aq^2) But x-coordinates of P and Q differ by (2a) So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2) So Q=(2a(p-1), aq^2) which means, 2aq = 2a(p-1) therefore, q=p-1 then I subbed that value of q in aq^2 so Q=(2a(p-1), a(p-1)^2) and P=(2ap,ap^2) Using these two values, I found the midpoint which was: M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 ) then x = a(2p-1) rearranging to make p the subject p= (x+a)/2a</span>
6 0
3 years ago
3/8 times what equals 1
horsena [70]
3/8 times 8/3 = 1
Answer=8/3
6 0
3 years ago
Please help me ASAP
stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24

Point (-2,-24)

\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6

Point (0,-6)

\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0

Point (2,0)

\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6

Point (4,-6)

\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24

Point (6,-24)

The graph is shown in the image below

8 0
2 years ago
ann arranges her marbles in groups, with 8 marbles in each group. She writes the fraction 5/8 to show the fraction of marbles in
DerKrebs [107]
If there are 8 marbles in a group , and 5 out of every 8 is red, than in six groups there would be 5, 10, 15, 20, 25, 30 red marbles.

This lists the group of 6 sets.

30 red marbles in 6 sets.
8 0
3 years ago
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