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Your answer is ..
First,
we have to turn our mixed fractions into an improper fraction.
=4 1/8 which is 33/8(4 x 8 + 1).
Our next mixed fraction,
we have 1 1/7 which is 8/7(1 x 7 + 1).
Now, we have the get the same denominator in order to subtract.
SO, both 8 and 7 goes in to 56. So we multiply both mixed fractions to get the same denominator.
(Tip: what ever you do to do numerator, you do to the denominator; and the other way around).
33/8 : 33*7=231 and our denominator, 8*7=56
So our improper fraction now,
231/56
Our next fraction 8/7,
7*8= 56 and our numerator 8*8=64.
=64/56
So, now we subtract.
231-64= 167 and our common denominator. 167/56
Now we divide 167 by 56 which is 2 and remainder is 55.
So, you should end up with a mixed fraction, 2 55/56.
The total tickets sold at the fair = 50 tickets.
Kayla and Bianca each bought one ticket, it could be any numbered. We can start with anyone and find their probability.
If Kayla got ticket numbered #7, its probability would be 1 out of 50.
Then there would be 49 tickets remaining for Bianca at the fair.
If Bianca got ticket numbered #10, it probability would be 1 out of 49.
Total probability of (Kayla getting #7 AND Bianca getting #10) would be 1/(50x49) = 1/(2,450) = 0.0004081 = 0.0408%.
Hence, final answer is 
Answer:
Advance ticket costs $25
Same-day ticket costs $20
Step-by-step explanation:
Let x = the price of one the advance ticket.
Let y = the price of one same-day ticket.
The combined cost of one advance ticket and one same-day ticket is $ 45. This means
x + y = 45 - - - - - - 1
For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means
30x + 20y = 1150 - - - - - - - - -2
From equation 1, x = 45- y
Put x = 45- y in equation 2
30( 45-y) + 20y = 1150
1350 - 30y + 20y = 1150
-10y = 1150-1350
-10y = -200
y = 200/10 = $20
x = 45-y
x =45-20= $25
Advance ticket costs $25
Same-day ticket costs $20
Answer:
1/4
Step-by-step explanation:
-7 - -9/4- -4
2/8 = 1/4