IF KOBE HAD 8 DUNKS AND LEBRON HAD 10, HOW MANY MORE DUNKS DID LEBRON HAVE THEN KOBE?
2 answers:
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Answer:
Step-by-step explanation:
By applying tangent rule in the given right triangle AOB,
tan(30°) =
By applying tangent rule in the given right triangle BOC,
tan(60°) =
OC = BO(√3)
OA + OC = AC
2√3(BO) = 60
BO = 10√3
OC = BO(√3)
OC = (10√3)(√3)
OC = 30
By applying tangent rule in right triangle DOC,
tan(60°) =
OD = OC(√3)
OD = 30√3
Since, BD = BO + OD
BD = 10√3 + 30√3
BD = 40√3
≈ 69.3
