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Stella [2.4K]
3 years ago
8

NEED HELP ASAP PLEASE

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

8.5%

Step-by-step explanation:

I=PRT

85= 2000*r*0.5

85=1000r

0.085=r

8.5%

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Suppose a mutual fund qualifies as having moderate risk if the standard deviation of its monthly rate of return is less than 5​%
Leokris [45]

Answer:

\chi^2 =\frac{28-1}{25} 21.7156 =23.453

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=28 represent the sample size

\alpha=0.1 represent the confidence level  

s^2 =21.7156 represent the sample variance obtained

\sigma^2_0 =25 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 25, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{28-1}{25} 21.7156 =23.453

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 27. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

4 0
3 years ago
Crystal earns $5.50 per hour mowing lawns. A. Write a rule to describe how the amount of money m earned is a function of the num
Ivahew [28]
She earns $20.625 in 3 hours and 45 mins
6 0
3 years ago
Help me please i’ll give extra points
vazorg [7]

Answer:

y=1

Step-by-step explanation:

20-18/6-4 = 2/2 = I

Hope this helped

3 0
2 years ago
Read 2 more answers
What do u notice to this picture?
trasher [3.6K]

Answer:

The picture has a pattern. The pattern in this picture is that each time 4 corners are added. You can also look at this as it adds 4 each time or as the equation. Y=5+4x. Y being The amount of cubes in the equation

3 0
3 years ago
How do you work this out?
oksian1 [2.3K]
I think this problem is 3
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