Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9
balu736 [363]
Given:
The function is
To find:
The missing values for a, b, and c in the given table.
Solution:
We have,
At x=-2,
![\left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cleft%28%5Cdfrac%7Ba%7D%7Bb%7D%5Cright%29%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7Bb%7D%7Ba%7D%5Cright%29%5E%7Bn%7D%5Cright%5D)
At x=-1,
At x=0,
![\left[\because a^0=1, a\neq 0\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20a%5E0%3D1%2C%20a%5Cneq%200%5Cright%5D)
Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.
9=30*25+25*53. which = 2975.
You have to split the shape into two smaller ones to make two rectangles and find the area of both and add them together.
With 12, you need to find the area of both shaped and subtract the triangle form the rectangle to get 93.5.
Answer:
a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %
Step-by-step explanation:
a. This is a binomial probability.
Let q = probability of giving out wrong number = 15 % = 0.15
p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75
For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹
= 10(0.15)(0.75)⁹
= 1.5(0.0751)
= 0.1126
= 11.26 %
b. At most one wrong is P(x ≤ 1) = P(0) + P(1)
= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹
= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹
= 0.0563 + 0.01126
= 0.06756
= 6.756 %
≅ 6.76 %
Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.
Answer:
Wasps with long wings can produce offspring with short wings.
Step-by-step explanation:
Answer:
214
Step-by-step explanation:
The set up would be x + (x + 1) + (x + 2) + (x + 3) = 854, naturally as the numbers are consecutive. Solving for x:
x + (x + 1) + (x + 2) + (x + 3) = 854,
x + x + 1 + x + 2 + x + 3 = 854,
4x + 1 + 2 + 3 = 854,
4x + 6 = 854,
4x = 854 - 6 = 848,
x = 848/4 = 212
The third number then should be 212 + 2 = 214
