the height can be given as
AB = a sin theta
here a = 4 and theta is 60 so
AB = 4 sin 60 = 4 × √3/2 = 2√3
so area of a parallelogram is
= base × height
= 7 × 2√3 = 14√3
Can anyone help me on question 5?
1 answer:
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the height can be given as
AB = a sin theta
here a = 4 and theta is 60 so
AB = 4 sin 60 = 4 × √3/2 = 2√3
so area of a parallelogram is
= base × height
= 7 × 2√3 = 14√3