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Mashcka [7]
3 years ago
5

Emily Works at an ice cream shop​

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

Aidan eats 2 ice cream and makes 100$

Step-by-step explanation:

Tju [1.3M]3 years ago
5 0
Bob eats the shop then goes to jail
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Classify the solid.<br> PLS HELPP
Kruka [31]
Trapezoidal Prism

It is a prism with 2 bases of shape trapezoid
7 0
3 years ago
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Dan earns $9.50 per hour as a dishwasher. Determine the fewest number of hours he must work to earn
Oksana_A [137]

Answer:

43 hours

Step-by-step explanation:

\frac{y}{1} :\frac{408}{9.5}

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

y=42\frac{18}{19}

43 hours

8 0
3 years ago
Read 2 more answers
please help me, im stuck and i do not understand what i need to do, answer the question in the picture please
tino4ka555 [31]

Answer:

x = - \frac{1}{4}

Step-by-step explanation:

To find f(g(x)) substitute x = g(x) into f(x), that is

f(g(x))

= f(x + 1)

= 2(x + 1)² ← expand using FOIL

= 2(x² + 2x + 1) ← distribute

= 2x² + 4x + 2

To find g(f(x)) substitute x = f(x) into g(x), that is

g(f(x))

= g(2x²)

= 2x² + 1

----------------------------------------------------------

Equating  gives

2x² + 4x + 2 = 2x² + 1 ( subtract 2x² + 1 from both sides )

4x + 1 = 0 ( subtract 1 from both sides )

4x = - 1 ( divide both sides by 4 )

x = - \frac{1}{4}

4 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Find the least common denominator <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B9%7D%20%5Cfrac%7B8%7D%7B4%7D" id="TexFormul
MA_775_DIABLO [31]

Answer:

36 is your least common denominator. Hope this helps

Step-by-step explanation:

8 0
2 years ago
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