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3 years ago

I need help i don’t understand this

Mathematics

2 answers:

DIA [1.3K]3 years ago

7 0

The flat line is always 180* the angle on the right says 138*. So you subtract 138 from 180 and you get 42*. So you put 42* as the Acute angle next to 138* on C.
It’s been a while since I did this next part so I may be wrong. But once you have the angle of two sides you add them and subtract them from 180 to get the third angle of the rectangle. So 82+42= 124, 180-124=56. So 56 is A

lys-0071 [83]3 years ago

6 0

Answer:
Angle BAC: 56
ANGLE BCA: 42

Why? First find angle BCA because that angle is on a straight line with another angle on the other side you can do
180-138=42 which is the measurement of angle BCA.

For angle BAC you have to know that the sun of all triangles interior angles is 180 so you do
180-82-42=56
So angle BAC is 56

Hope this helps :D

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Hii can someone help with this pls :)

BlackZzzverrR [31]

Answer:

$R(x,y) = (0.8,-1.2)$

Step-by-step explanation:

The coordinates of QS are:

$Q(x_1,y_1) = (-2,-6)$

$S(x_2,y_2) = (5,6)$

The ratio is represented as:

$R_{m:n} = 2:3$

Required

Find the coordinates of R

The coordinates of R is calculated by:

$R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Substitute values for m, n, x's and y's

$R(x,y) = (\frac{2 * 5 + 3 * -2}{2+3},\frac{2*6 + 3*-6}{2+3})$

$R(x,y) = (\frac{4}{5},\frac{-6}{5})$

$R(x,y) = (0.8,-1.2)$

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3 years ago

Triangle ABC has vertices A(-3,0) B(0,6) C(4,6). Find the equations of the three medians of triangle ABC

Mariana [72]

Answer:

1. $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

2. $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$

Step-by-step explanation:

A(−3, 0), B(0, 6), and C(4, 6)

using the midpoint formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$ we can find all of their midpoint which is necessary to complete question 1 and 2

Mid AB=(-1.5, 3), Mid BC=(2, 6), Mid AC=(0.5,3)

Next, we have to find the slope of from the vertex and the midpoint of each side. We use the slope formula: $\frac{y_2-y_1}{x_2-x_1}$ .

You would get -6, 6/5, and 6/11.

Next you substitute in the coordinates for the equation of each for example: y=-6x, you switch in the set of cords AB which is (-1.5, 3). 3=-6(-1.5)+z and find that z=6, so the equation is y=-6x+6. As for the rest, repeat the same process until you find all 3 cords. You should get an answer of $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

For question 2,

The line has to be perpendicular bisector to the midpoint, signifying that it has to split 2 angles into congruent angles and a side into half. In order to do that we need to first find the opposite reciprocal of each side's slope. Which means we need to once again use the slope formula and get the opposite reciprocal by $-\frac{1}{slope}$ . For all the opposite reciprocal slopes you get will be incorporated into the final formulas. That gives us the slopes of -1/2, 0 and -7/6. Then do the same process of matching cords with these incomplete equations and you can find the final equations of $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$

I hope that helped with your question!! :)

Also I'm an RSM student too and I didn't know how to do them before so I searched it up.

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