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3 years ago

What is the area of the following trapezoid? 13.5 yd 2 3.38 yd 2 6.75 yd 2 8.25 yd 2

Mathematics

1 answer:

Neporo4naja [7]3 years ago

8 0

Answer:

$area = \frac{a + b}{2} h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2 + 7}{2} \times 1.5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6.75 {yd}^{2}$

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

Choose the improper fraction that is equivalent to the mixed number 2 17/24

Alborosie

Answer:

31/24

Step-by-step explanation:

multiple 2 by 24, then add 17, which you get 31, and put it over 24

31/24

8 0

3 years ago

Read 2 more answers

Consider the following region R and the vector field Bold Upper F.

Natali5045456 [20]

Answer and Step-by-step explanation:

Workings and solutions to a, b, & c can be viewed in the snapshot below:

7 0

4 years ago

Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.

Keith_Richards [23]

Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

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3 years ago

If b = 7 and A = 80 degrees,<br> find c.

bixtya [17]

Answer:

Step-by-step explanation:

7/sin10=c

c=40.31

6 0

3 years ago