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2 years ago

35 POINTS HELP PLS!!!!!!

Mathematics

1 answer:

Ronch [10]2 years ago

8 0

The factors illustrate they the sides of the rectangles are:

(x - 1)(x - 2)
(2x - 3)(x + 2)

<h3>How to get the factors?</h3>

The first equation given is x² - 3x + 2.

= x² - 3x + 2.

= x² - x - 2x + 2

= x(x - 1) - 2(x - 1)

= (x - 1)(x - 2)

Therefore, the side lengths are (x - 1) and (x - 2).

In the rectangular figure, the length and width should be the expressions above.

The second equation given is 2x² + x - 6.

= 2x² + x - 6.

= 2x² + 4x - 3x - 6

= 2x(x + 2) - 3(x + 2)

= (2x - 3)(x + 2)

Therefore, the side lengths are (2x - 3) and (x + 2).

In the rectangular figure, the length and width should be the expressions above.

Learn more about factor on:

brainly.com/question/219464

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Answer:

Step-by-step explanation:

=> -4+9

=> 5

Cuz first u have to do 4 plus 5, which'll be 9. And then, since -4 is negative, we have to subtract 9 from 4. So the answer's 5.

Make me brainliest :))))

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3 years ago

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The correct answer is A. The total points Shelly earned

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3 years ago

Simplify -8/9 ÷ 6/-3. <br> A-4 <br> B2 <br> C−2 <br> D 4

77julia77 [94]

Exact Form:
4/9
Decimal Form:
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3 years ago

Read 2 more answers

Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

7 0

3 years ago

Simplify this expression (d + 5) + (d + 5) + (d + 5)

kicyunya [14]

Answer:

3d + 15

Step-by-step explanation:

(d + 5) + (d + 5) + (d + 5) =

d + 5 + d + 5 + d + 5 =

(d + d + d) + (5 + 5 + 5) =

3d + 15

4 0

3 years ago