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Alecsey [184]
3 years ago
10

What are three types of sillicones​

Mathematics
1 answer:
Luden [163]3 years ago
8 0

Answer:

Silicone types in common use in the industry include:

High Modulus.

Low modulus.

Neutral cure.

Acetoxy cure.

Hope u won't forget to mark brainiest

have a good day!

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Which of the following is the correct decimal and percent for the fraction 3/10?
goldenfox [79]

0.3, 30% is the correct answer

8 0
3 years ago
BRAINLEYEST! POINTS AND 5 STARS! TO RIGHT ANSWER! you have to order the boxes to where there soppost to be just order it with th
nikitadnepr [17]

Answer:

It would be

6

4

1

5

3

2

Step-by-step explanation:

The first one would equal 7

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the third one would equal 9

The fourth one would equal 6

The fifth would equal 8

ANd the sixth would equal 3

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2 years ago
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My room is 7½ ft by 8 ¼ ft. If I want to put a border around it l mid help​
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2 years ago
Find a closed form for the generating function for each of these sequences. (assume a general form for the terms of the sequence
noname [10]
There really is no single "obvious" choice here...

Possibly the sequence is periodic, with seven copies of -1 followed by six copies of 0, or perhaps seven -1s and seven 0s. Or maybe seven -1s, followed by six 0s, then five 1s, and so on, but after a certain point it would seem we have to have negative copies of a number, which is meaningless.

Or maybe it's not periodic, and every seventh value in the sequence is incremented by 1? Who knows?

I'll go ahead and assume the latter case, that the sequence is not periodic, since that's technically somewhat easier to manage. We can assign the following rule to the n-th term in the sequence:

\{a_n\}=\{-1,\ldots,-1,0,\ldots,0,1,\ldots,1,2,\ldots,2,3,\ldots\}
\implies a_n=\left\lfloor\dfrac n7\right\rfloor-1

for n\ge0.

So the generating function for this sequence might be

G(a_n;x)=\displaystyle\sum_{n\ge0}\left(\left\lfloor\frac n7\right\rfloor-1\right)x^n

As to what is meant by "closed form", I'm not sure. Would this answer be acceptable? Or do you need to find a possibly more tractable form for the coefficient not in terms of the floor function?
4 0
3 years ago
PLEASE HELP<br> ANSWER SERIOUSLY
alex41 [277]

Answer:

raise a product to a power.

you first simplify the parenthesis in the numerator by raising 2 by the power of three and multiplying the exponents.

i suck at explaining, but after the first step the expression looks like:

(\frac{8r^{6}t^{3}  }{4t^{2} })^{2}

Step-by-step explanation:

5 0
3 years ago
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