Your answer will be letter c
Given that total number of books in the book store = 75972
Given that total number of books in science section =
rd of total books =
= 25324
Then remaining number of books = 75972 - 25324 = 50648
Given that 75% of the remaining books are in business section = 75% of 50648 = 0.75*50648 = 37986
Then number of books in the math section = 50648 - 37986 = 12662
Hence final answer is 12662 books in the math section.
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
Answer:
For 36 movies the cost of both the plans is same.
Step-by-step explanation:
Let us assume foe m movies, both the plans cost same.
Now, PLAN A:
Annual Fee = $45
Cost per movie = $2.50
⇒The cost of watching m movies = m x (Cost of 1 movie)
= m x ($2.50) = 2.5 m
So, the total cost of Plan A = Annual Fee + Cost of m moves
= 45 + 2.50 m
PLAN B:
Cost per movie = $3.75
⇒The cost of watching m movies = m x (Cost of 1 movie)
= m x ($3.75) = 3.75 m
ACCORDING TO QUESTION:
for m movies, Cost of plan A = Cost of plan B
⇒45 + 2.50 m = 3.75 m
or, 3.75 m - 2.5 m = 45
or, m = 45/1.25 = 36
or, m = 36
Hence, for 36 movies the cost of both the plans is same.
