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2 years ago

What theorem can be used to prove the 2 triangles similar?

Mathematics

1 answer:

ASHA 777 [7]2 years ago

6 0

Answer:

C. SSS

Step-by-step explanation:

$\frac{AB}{SQ} = \frac{AC}{SR} = \frac{BC}{QR} = 2$

Thus, the ratio of the corresponding side lengths of both triangles are equal. This implies that all three corresponding side lengths of both triangles are proportional to each other.

Consequently, based on the SSS Criterion, we can conclude that both triangles are similar to each other.

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Answer:

a reflection across line y, then a translation (1,-5) (right 1, down 5)

Step-by-step explanation:

A(-2,4) → (2, 4) → D(3, -1)

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3 years ago

A few years ago, a census bureau reported that 67.4% of American families owned their homes. Census data reveal that the owner

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With this conclusion city council does not continue tax cut, and citizens of the city is harmed because they lose help they could have used to buy a home.

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3 years ago

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3 years ago

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Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

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3 years ago