All categories

3 years ago

The product of nine and n

Mathematics

2 answers:

antoniya [11.8K]3 years ago

5 0

Answer:

9n?

Step-by-step explanation:

i think its 9n its been a while ok

masha68 [24]3 years ago

4 0

Answer:

9 x n

Step-by-step explanation:

The ¨product¨ is the answer to a multiplication problem, so that requires you to multiply 9 and n.

You might be interested in

I need help with this.

Sloan [31]

9514 1404 393

Answer:

61.4

Step-by-step explanation:

The length of two semicircles of diameter 10 is the circumference of a circle of that diameter:

C = πd = 10π ≈ 31.4

The perimeter includes that length plus the lengths of two straight sides that are 15 units each.

P = 31.4 + 2×15

P = 61.4 . . . . units

4 0

3 years ago

Evaluate square root 16 minus x when x = 8. Write the answer in simplified radical form.

PtichkaEL [24]

Answer -4
___
-/ 16 = 4 X=8

4-8= -4

3 0

3 years ago

Read 2 more answers

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Can I get some help ???

Nikitich [7]

Answer is D. <em><u>288</u></em> . i am glad to help

4 0

3 years ago

Suppose an engineer has been instructed to create three new sky rides in the park. He has been given the length and the time eac

Tanya [424]

Answer:

Step-by-step expla

la respuesta esnation:

3 0

3 years ago