All categories

2 years ago

Which of the binomials below is a factor of this trinomial ? 8x^2+ 2x-3

Mathematics

1 answer:

zhenek [66]2 years ago

7 0

Answer:

(2x-1) and (4x+3) are the factors of the trinomial.

Celebration! Hope this helps ^_^

You might be interested in

Follow the process of completing the square to solve x^2 - 10x + 8 = 0. What is the value of the constant that will be isolated

My name is Ann [436]

To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33

7 0

3 years ago

Read 2 more answers

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug

timurjin [86]

11 bottles are needed to fill a 16 liter jug

Solution:

Given that, there is a 16 liter jug

There are $1\frac{1}{2}$ liters of bottle

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

$\rightarrow 1\frac{1}{2} = \frac{2 \times 1 + 1}{2} = \frac{3}{2} = 1.5$

Thus the bottle is of 1.5 liter

We have to find the number of 1.5 liter bottles needed to fill 16 liter jug

Divide 16 by 1.5 to get result

$Number\ Of\ Bottles = \frac{16}{1.5} = 10.67 \approx11$

Thus 11 bottles are needed to fill a 16 liter jug

7 0

3 years ago

7x^2=9+x what are the values of x Will give medal and points

DENIUS [597]

7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in the a, b, and c values
x = $\frac{- (-1) \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Cancel out the double negative
x = $\frac{1 \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Square -1
x = $\frac{1 \pm \sqrt{1 - 4(7)(-9)} }{2(7)}$ Multiply 7 and -9
x = $\frac{1 \pm \sqrt{1 - 4(-63} }{2(7)}$ Multiply -4 and -63
x = $\frac{1 \pm \sqrt{1 + 252} }{2(7)}$ Multiply 2 and 7
x = $\frac{1 \pm \sqrt{1 + 252} }{14}$ Add 1 and 252
x = $\frac{1 \pm \sqrt{253} }{14}$ Split up the $\pm$
x = $\left \{ {{ \frac{1 + \sqrt{253} }{14} } \atop { \frac{1 - \sqrt{253} }{14} }} \right.$
The approximate square root of 253 is 15.905973.
x ≈ $\left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right$ Add and subtract
x ≈ $\left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.$ Divide
x ≈ $\left \{ {{1.2075} \atop {1.0647}} \right.$ Round to the nearest hundredth
x ≈ $\left \{ {{1.21} \atop {1.06}} \right.$

7 0

3 years ago

If you reflect ABCD across x-axis, what will be the coordinates of A’ and C’

disa [49]

Answer:

A (1, -5), B (2, -5)

8 0

3 years ago

Read 2 more answers

What is the value of A

Keith_Richards [23]

I think the answer is a = 4.5