Distance covered along the slope is 48 m
Explanation:
A uniform motion is a motion in which the velocity is constant. The distance covered by an object during a uniform motion is given by
where
v is the velocity
t is the time
Here we have:
v = 0.8 m/s (velocity)
t = 1 min = 60 s
Therefore, the distance covered along the slope is:
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Increase because the mass of an object aligns with its weight
Answer:
radius of curvature is 1.2 m
Explanation:
given data
distance u = 30 cm
to find out
radius of curvature
solution
we know radius of curvature is double of focal length
so we find focal length
lens formula for focal length
1/f = 1/u + 1/v ..............................1
so here from magnification
M = - u /v
2 = - u /v )
v = -2u = -2(30)
v =- 60 cm
so from equation 1
1/f = 1/u + 1/v
1/f = 1/30 + 1/-60
f = 60.02 cm
so R = 2f
R = 2( 60.02)
R = 120.04 cm
so radius of curvature is 1.2 m
Answer:
The height of the building is 88.63 m.
Explanation:
Given;
initial component of vertical velocity, = 12 m/s sin 26° = 5.26 m/s
initial horizontal component of the velocity, = 12 m/s cos 26° =10.786 m/s
horizontal distance traveled by the rock, x = 40.4 m
time of flight is calculated as;
x = t
t = x /
t = 40.4 / 10.786
t = 3.75 s
Determine the final vertical velocity of the ball;
Determine the height of the rock;
Therefore, the height of the building is 88.63 m.
Conduction. is a transfer of energy by direct contact