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Paul [167]
4 years ago
14

The ΔG of a reaction would be at the minimum when... Group of answer choices the equilibrium constant is equal to 1 (i.e., the r

eactant and product concentrations are always equal). the reactant and product concentrations don't change over time (the system is at equilibrium). the entropy has reached its maximum positive value. the reaction goes to completion. the reaction is very slow
Physics
1 answer:
Blizzard [7]4 years ago
5 0

Answer:

the equilibrium constant is equal to 1 (i.e., the reactant and product concentrations are always equal).

Explanation:

ΔG is a symbol related to Gibbs free energy, which is a physical quantity related to thermodynamics. ΔG refers to the difference between the change in enthalpy (and sometimes entropy) and the temperature of a chemical reaction.

Gibbs free energy is very useful for measuring the work done between the reactants in a reaction. It is calculated using the formula: ΔG = change in enthalpy - (temperature x change in entropy).

The ΔG of a reaction would have a minimum value (zero), if the equilibrium constant is equal to 1 (that is, the concentrations of the reagent and the product are always equal).

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In a nuclear power plant, _____. energy is released from the nuclei of atoms energy is released from the bonds of molecules ener
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In a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per c
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Answer:

1 mm^3 = 1.0 x 10^-9 m³

Hence;

5.23 x 10^-6 kg/mm^-3 = (5.23 x 10^-6 kg)/ 1x10^-9 m³

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10. If the gravitational force between two objects of equal mass is found to be 4.60*10^-6 N when the objects are 15 meters apar
liraira [26]

Answer:

Explanation:

F = G*m1 * m2 / r^2

G = 6.67408 × 10-11 m3 kg-1 s-2

r = 15 m

F = 4.60 * 10^-6 N

m1 = m2 = m

F = 6.67 * 10^-11 * m^2 / 15^2

4.60 * 10^-6 = 6.67 * 10^-11 * m^2 / 225            Multiply both sides by 225

4.60*10^-6 * 225 = 6.67*10^-11 * m^2

.001035 =  6.67408 × 10-11 * m^2                     Divide by  6.67408 × 10-11

0.001035/ 6.67408 × 10-11 = m^2

m^2 = 15507755                                                Take the square root of both sides

m = sqrt(15507755   )

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5 0
3 years ago
A 0.51-kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12 m to 0.23 m (relative to it
den301095 [7]

Answer:

487.23 N/m

Explanation:

Given:

mass of metal sphere 'm'= 0.51kg

the spring stretches from 0.12 m to 0.23 m. Therefore,

s_1}= 0.12m and s_{2}= 0.23m

the speed of the sphere decreases from 6.7 to 3.3 m/s. Therefore,

v_{1}= 6.7m/s and v_2}=3.3m/s

In order to find spring constant, we apply law of conservation of energy. i.e

The change of the kinetic energy of sphere is equal to the change of potential energy of the spring.

So, ΔE_{k} = ΔE_{v}

where,

ΔE_{k} = 1/2 m (v_{1}- v_2})²

ΔE_{v}= 1/2 k (s_1} - s_{2})²

1/2 m (v_{1}- v_2})² = 1/2 k (s_{2}- s_1} )²

k= m [ (v_{1}- v_2})²/(s_{2}- s_1} )²

k= 0.51 [(6.7-3.3)²/ (0.23-0.12)²]

k= 487.23 N/m

Thus, the spring constant of the spring is 487.23 N/m

5 0
4 years ago
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