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2 years ago

What happens in a tug of war if the net forces are balanced and why?

Physics

1 answer:

FinnZ [79.3K]2 years ago

6 0

Answer:

Balanced forces are responsible for unchanging motion. Balanced forces are forces where the effect of one force is cancelled out by another. A tug of war, where each team is pulling equally on the rope, is an example of balanced forces. The forces exerted on the rope are equal in size and opposite in direction.

Explanation:

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A bald eagle is flying to the left with a speed of 34 meters

Shtirlitz [24]

Answer:

the speed after 3 seconds is 10 m/s

Explanation:

The computation of the speed is shown below:

As we know that

V = U + at

Here,

U = 34 m/s

a = - 8 m/s²

t = 3 Sec

V = velocity after 3 sec

V = 34 + (-8)3

= 34 - 24

V = 10 m/s

Hence, the speed after 3 seconds is 10 m/s

4 0

2 years ago

A 10 kg brick and a 1 kg book are dropped in a vacuum. The force of gravity on the 10 kg brick is what?

Nadya [2.5K]

<span>10 times as much. Since F=m*a, and a is constant, the only thing that affects force is the mass.

In response to the below answer, the acceleration due to gravity does not change. The force due to gravity definitely DOES change depending on the mass of the object. Since the force is what the problem asks for, the answer is 10</span>

7 0

2 years ago

Read 2 more answers

Determine the value of the current in the solenoid so that the magnetic field at the center of the loop is zero tesla. Justify y

sleet_krkn [62]

Answer:

I will explain the concept of magnetic field and how it can be calculated.

Explanation:

The formula for magnetic field at the center of a loop is given as

B = μ $_{o}$ I / 2R

where B is the magnetic field

R is the radius of the loop

I is the current

and μ $_{o}$ is the magnetic permeability of free space which is a constant 4π × $10^{-7}$ newtons/ampere²

If the magnetic field at the center of the loop is 0, then μ $_{o}$ I = 0

I = 0 which means there will be no current flow in the loop.

3 0

2 years ago

How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at

Maru [420]

Well you of course have different kinetic energies with the two speeds.
Kinetic energy = (1/2)*mass*velocity^2
The vehicle's mass is the same in both cases, so we can ignore that as well as 1/2 since it's a constant.
So we have (30)^2 vs (60^2)
which is 900 vs 3600
So having 60 mph compared to 30 mph is 4 times the kinetic energy.

5 0

2 years ago

An object moves uniformly around a circular path of radius 19.0 cm, making one complete revolution every 2.40 s.

klio [65]

Answer:

v = 0.5 m/s

f = 0.42 Hz

ω = 2.6 rad/sec

Explanation:

By definition, the translational speed is the rate of change of the position with respect to time.
The change in position along a complete revolution is just the following:
Δs = 2*π*r = 2*π*0.19 m = 1.19 m
The time needed to complete a revolution is 2.4 s, so the translational speed can be written as follows:

$v =\frac{\Delta s}{\Delta t} = \frac{1.19m}{2.4s} = 0.5 m/s (1)$

The frequency in Hz is just the inverse of the time needed to complete a revolution (known as the period T), as follows:
f = 1/T = 1/2.4s = 0.42 Hz (2)
Finally, the angular speed is the rate of change of the angle rotated with respect to time, as follows:

$\omega = \frac{\Delta\theta}{\Delta t} = \frac{2*\pi}{2.4s} = 2.6 rad/sec (3)$

5 0

2 years ago