Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)
To get the probability of less than 109.1 cm, the solution is computed by:
z (109.1) = (X-mean)/standard dev
= 109.1 – 108/ 0.6
= 1.1/0.6
=1.83333, look this up in the z table.
P(x < 109.1) = P(z < 1.8333) = 0.97 or 97%
1.) D = 2pi * d * A / 360 degrees; Where:
pi = 3.14;
d = distance or 56,000,000 km (5.6x10^7 to standard notation)
A = angular size in degrees or .00688 degrees (.00012 radian to degrees)
D = 2(3.14) * 56,000,000 * .00688 / 360
= 6.28 * 385,280 / 360
= 2,419,558.4 / 360
D = 6,720.996 or 6,721
Therefore, 6,721 km. is the approximate diameter of Mars.
Answer: You just need to draw a line
Step-by-step explanation: Place a dot on positive 2 on the y-axis, then go down 7 and 1 to the right. If it doesn’t go all the way down, make your own point to make it seem like it will land where it has to be and connect it to the positive 2. It has to be a straight line
Answer:
176000cm
Step-by-step explanation:
1.76km * 1000m / 1km * 100cm / 1m = 176000cm